the two thin plano-convex lenses, each of focal length 40cm are combined to form a bioconvex lens. how far from thislens should an object be placed such that its inverted image of unit magnification is formed on the other side of the lens?
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Answer:
f=40cm
feq=
80
40×40
=20cm
the image formed when object is placed at the center of curvature is real, inverted and unitly magnified.
c=2f=2×20=40cm
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Given:
Focal length, f = + 40 cm
Magnification, m = - 1 (as the image will be real and inverted due to convex lens)
To Find:
Object distance, i.e., u
Calculation:
- Applying the relation between magnification, focal length and object distance, we get:
m = f / (f + u)
⇒ u = f × (1 - m) / m
⇒ u = 40 × {1 - (-1)} / (-1)
⇒ u = - 80 cm
- So the object should be placed at a distance of 80 cm from the lens to get the required image.
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