The two vectors î +j+k and î + 3j + 5k
represent the two sides AB and AC
respectively of a AABC. The length of
the median through A is
(A)
14
(B) 7
Answers
Answered by
6
Answer:
√14
Step-by-step explanation:
AB = i+j+k => (0,0,0) to (1,1,1)
AC = i+3j+5k => (0,0,0) to (1,3,5)
Midpoint between (1,1,1) and (1,3,5)
=> (2/2,4/2,6/2) = (1,2,3)
=> (0,0,0) to (1,2,3) = i+2j+3k
Magnitude of i+2j+3k = √(1+2²+3³) = √14
Similar questions