Question

The two vertices of a triangle are (3,-5), (10,-2) and its centroid is (2,-1). Find its third vertex.

Answer 1

Answer:

Step-by-step explanation:

Let (3,-5) be (x1,y1)

(10,-2) be (x2,y2)

(2,-1) be (x,y)

By centroid formula,

x=x1+x2+x3/3 y=y1+y2+y3/3

2=3+10+x3/2 -1=-5-2+y3/3

2×3=13+x3 -1×3=-7+y3

6=13+x3 -3=-7+y3

x3=6-13=-7 y3=-3+7=4

Third vertice (-7,4)