Question

the two white triangle is divided into three equal parts feel is one third part with a different colour can you show that these parts are equal think how​

Answer 1

$\huge \color{aqua}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf f(x) & \bf \displaystyle \int \rm \:f(x) \: dx\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf k & \sf kx + c \\ \\ \sf sinx & \sf - \: cosx+ c \\ \\ \sf cosx & \sf \: sinx + c\\ \\ \sf {sec}^{2} x & \sf tanx + c\\ \\ \sf {cosec}^{2}x & \sf - cotx+ c \\ \\ \sf secx \: tanx & \sf secx + c\\ \\ \sf cosecx \: cotx& \sf - \: cosecx + c\\ \\ \sf tanx & \sf logsecx + c\\ \\ \sf \dfrac{1}{x} & \sf logx+ c\\ \\ \sf {e}^{x} & \sf {e}^{x} + c\end{array}} \\ \end{gathered}\end{gathered}\end{gathered}$

Answer 2

Answer:

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Step-by-step explanation:

Since one triangle is divided into three equal parts, therefore, each part is one-third of the whole triangle. Let us in each part and colour them in a different colour as shown in the above figure. ... We find that T1 covers T1, T2 and T3 are of the same shape and size. Hence, these triangles are equal.