Question

the two zeroes of a quadratic polynomial are-4 and-6 find the sum and product of the zeroes what is the value of cofficient ?​

Answer 1

Answer:

sum = -10

product = 24

value of coefficient = -4

Step-by-step explanation:

-4+-6=-10

-4*-6=24

coefficient is highest tem of x

implies -4

Answer 2

Answer:

The value of the coefficient are

a = 1  

b = 10  

c = 24

Step-by-step explanation:

The zeros of a quadratic polynomial are -4 and -6

Let α = -4   and   β = -6

Sum of the zeros α + β = -4 + -6 = -10

Product of zeros αβ      =  (-4 ) ( -6 ) = 24

To find the quadratic polynomial-

if α and β are the zeros then the quadratic polynomial =

k [ $x^{2}$ - ( α + β )x +αβ ]

⇒ k [ $x^{2}$ - ( -10 )x + 24 ]

⇒ k [ $x^{2}$ + 10x + 24 ]

If k = 1

then ⇒  1 [ $x^{2}$ + 10x + 24 ]

=  $x^{2}$ + 10x + 24

The required polynomial is $x^{2}$ + 10x + 24

The standard form of a quadratic polynomial = a$x^{2}$ + bx +c

In  $x^{2}$ + 10x + 24

a = 1   b = 10   c = 24

hope this helps you