the two zeros of a quadratic polynomial are -4 and -6 find the sum and product of the zeros what is the value of coefficient
b
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Sum of zeroes = -(coefficient of x) / coefficient of x^2
-4+(-6) = -b/a
-4-6 = -b/a
-10 = -b/a
B/a = 10
Product of zeroes = constant term / coefficient of x^2
-4*-6 = c/a
24 = c/a
So ,the value of b = 10
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