the two zeros of a quadratic polynomial are -4 and -6 find the sum and product of the zeros what is the value of ccoefficient b
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Sum of zeroes = -4-6=-10= -b/a
Product of zeroes = -4*-6=-24=c/a
Thus if we take a=1 b=-10 c=-24
Therefore the quadratic polynomial will be x^2-10x+24.
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Answer:
Sum of zeroes = -(coefficient of x) / coefficient of x^2
-4+(-6) = -b /a
-4-6= -b/a
-10 = -b/a
B/a = 10
Product of zeroes = constant term / coefficient of x^2
-4*-6 = c/a
24= c/a
So , value of a = 1 , b= 10 and c = 24
Hope it help you ✌️❣️
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