Chemistry, asked by vaibhavmalhotra977, 11 months ago

The type of hybridization in xenon atom and the number of
lone pairs present on xenon atom in xenon hexafluoride
molecule are respectively
(a) sp³d³ , one (b) sp³d³ , two
(c) sp³d³ , two (d) sp³d² , zero

Answers

Answered by aryanchauhan2424
1

Answer:

Hybridization: sp3d3

Lone pairs:2

(In xef6 )

.

.

It might helps you

Explanation:

Answered by jitumahi435
1

The correct option is "(a) sp³d³ , one".

Explanation:

  • Xenon has 8 electrons in its valence shell.
  • The type of hybridization in xenon atom is d^{2}sp^{2}
  • Xenon hexaflouride has 7 electron pairs of which 6 are bonding pairs and one is lone pair
  • There is migration of 2 electrons of p to d orbital which forms sigma bond between flourine atom.
  • Name of the Molecule formed by xenon - Xenon Hexafluoride
  • Its geometry is Distorted Octahedral
  • The Molecular Formula isXeF_{6}.
  • The hybridization is sp³d³

Therfore, the hybridisation is sp³d³ and the lone pair is one.

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