Chemistry, asked by vaibhavmalhotra977, 1 year ago

The type of hybridization in xenon atom and the number of
lone pairs present on xenon atom in xenon hexafluoride
molecule are respectively
(a) sp³d³ , one (b) sp³d³ , two
(c) sp³d³ , two (d) sp³d² , zero

Answers

Answered by aryanchauhan2424
1

Answer:

Hybridization: sp3d3

Lone pairs:2

(In xef6 )

.

.

It might helps you

Explanation:

Answered by jitumahi435
1

The correct option is "(a) sp³d³ , one".

Explanation:

  • Xenon has 8 electrons in its valence shell.
  • The type of hybridization in xenon atom is d^{2}sp^{2}
  • Xenon hexaflouride has 7 electron pairs of which 6 are bonding pairs and one is lone pair
  • There is migration of 2 electrons of p to d orbital which forms sigma bond between flourine atom.
  • Name of the Molecule formed by xenon - Xenon Hexafluoride
  • Its geometry is Distorted Octahedral
  • The Molecular Formula isXeF_{6}.
  • The hybridization is sp³d³

Therfore, the hybridisation is sp³d³ and the lone pair is one.

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