The uncertainity in the position of a moving bullet of mass 10 g is 10⁻⁵ m. Calculate the uncertainty in its velocity.
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Answered by
72
According to uncertainty principle ,
∆x.m∆v = h/4π
∴ ∆v = h/4πm∆x
Here given,
m = 10g = 0.01 kg
∆x = 10⁻⁵ m
h = 6.626 × 10⁻³⁴ J.s
Now, ∆v = 6.626 × 10⁻³⁴/{ 4 × 3.14 × 0.01 × 10⁻⁵ )
= 5.27 × 10⁻²⁸ m/s
Hence, uncertainty in its velocity = 5.27 × 10⁻²⁸ m/s
∆x.m∆v = h/4π
∴ ∆v = h/4πm∆x
Here given,
m = 10g = 0.01 kg
∆x = 10⁻⁵ m
h = 6.626 × 10⁻³⁴ J.s
Now, ∆v = 6.626 × 10⁻³⁴/{ 4 × 3.14 × 0.01 × 10⁻⁵ )
= 5.27 × 10⁻²⁸ m/s
Hence, uncertainty in its velocity = 5.27 × 10⁻²⁸ m/s
Answered by
3
Answer:
Explanation:
According to uncertainty principle of Heisenberg ,
∆x.m∆v = h/4π [where Δx=uncertainity in position,
∴ ∆v = h/4πm∆x h = planck's constant and π = pi ]
Here given,
m = 10g = 0.01 kg
∆x = 10⁻⁵ m
h = 6.626 × 10⁻³⁴ J.s
Now, ∆v = 6.626 × 10⁻³⁴/{ 4 × 3.14 × 0.01 × 10⁻⁵ )
= 5.27 × 10⁻²⁸ m/s
Hence, uncertainty in its velocity = 5.27 × 10⁻²⁸ m/s
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