Physics, asked by junaid3860, 1 year ago

The uncertainty in momentum of an electron is 1×10-5 kg ms the uncertainty in its position will be

Answers

Answered by Kanagasabapathy
11
Heya!!!

we know that ∆x.∆p≥h/4π

→1×10^-5×∆x≥6.6×10^-34/4×3.14

→∆x≥6.6×10^-34/(4×3.14)(10^-5)

→∆x≥0.525×10^-29

→∆x≥5.25×10^-30m

the minimum value is 5.25×10^-30m

I hope this will help u ;)
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