Question

the uncertainty in momentum of an electron is 1 x 10 ^-5 kg-m^2/s. the uncertainty in its position will be ( h = 6.62 x 10^-34 kg-m^2/s)

Answer 1

∆p.∆x= h/4π => (1×10^-5)(∆x)= 6.620×10^-34/4×3.14 => ∆x= 66.26/12.56 ×10^-35/10^-5 = 5.275 ×10^-30 m. Hope it helps you...