the uncertainty in position of an electron is equal to its de-Broglie wavelength. the minimum percentage error in its measurement of velocity under this circumstancewill be approximately?
Answers
Answered by
1
Answer:
Hi friend
Hope this answer helps you
Explanation:
The uncertainty in position is equal to de Broglie wavelength.
⟹Δx=λ=
mv
h
....... (1)
The Heisenberg's uncertainty principle is ΔxΔv≥
4πm
h
...... (2)
From equations (1) and (2),
(
mv
h
Δv≥
4πm
h
)
Thus,
v
Δv
≥
4π
1
Hence, minimum percentage error =
v
Δv
×100=
4π
100
=7.96≈8.
Similar questions