Question

The uncertainty in position of an electron (m=9.1×10−28gm) moving with a velocity 22×10^2m/s accurate upto 0.001% will be​

Answer 1

Answer:

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Explanation:

According to Heisenberg’s uncertainty principle, the product of uncertainties in position (Δx) and velocity △v≥hnπ

Question says, “accurate up to 0.001%”.

This indicates that the uncertainty in velocity is 0.001% of actual value, 300 m.s-1

That is, uncertainty in velocity (Δv) = 300×0.001100 = 3 x 10-3 m.s-1

Therefore, the uncertainty in position (Δx) can be calculated as follows:

△x=h4πm△u △x=6.626×10−34××1004×3.14×9.1×10−31×0.001×300 = 1.93*10-2m.