Question

The uncertainty in the velocity of a particle of mass 6.626*10^-28 kg is 1*10^-6ms^-1.what is the uncertainty in its position?

Answer 1

∆v=1×10^-6

∆v=1×10^-6m=6.626×10^-28

∆v=1×10^-6m=6.626×10^-28∆x.m∆v=h/4π

∆v=1×10^-6m=6.626×10^-28∆x.m∆v=h/4π∆x=h/4πm∆v

∆v=1×10^-6m=6.626×10^-28∆x.m∆v=h/4π∆x=h/4πm∆v =6.6×10^-34/4×3.14×6.6×10^-28×10^-6

∆v=1×10^-6m=6.626×10^-28∆x.m∆v=h/4π∆x=h/4πm∆v =6.6×10^-34/4×3.14×6.6×10^-28×10^-6 =0.079