Question

The uncertainty in velocity of an electron present in the nucleus of diameter10^15m hypothetically should be approximately??? Explain in steps

Answer 1

Δx . Δp = h/(4 π)

Δx . mΔv = h/(4 π)

Δv = h / (4 π × Δx × m)
= 6.626 × 10^-34 / (4 π × 10^-15 m × 9.1 × 10^-31)
= 5.8 × 10¹⁰ m/s

Uncertainty in velocity is 5.8 × 10¹⁰ m/s

This velocity is greater than velocity of light. That is the reason why electron can’t stay inside the nucleus.

[Note: You have mantioned that the diameter of ATOMIC NUCLEUS is 10¹⁵ m which is approximately 78 million times of diameter of earth. So, I took diameter of atomic nucleus as 10⁻¹⁵ m]

Answer 2

hope it helps please mark as brainliest 0.058 can be negated it is less than 1 so answer becomes 10 the power 11 meters per second