Question

the unequal side of an isoceles triangle measures 24 cm and its area is 60 cm square. find the perimeter of the given isosceles triangle​

Answer 1

Step-by-step explanation:

area=60

1/2×b×h=60

1/2×24×h=60

h=60×2×1/24

=5

So,perimeter=S+S+S

=24+5+5

=34cm

Answer 2

SoluTion :-

Let each equal side of isosceles triangle be x cm

$\sf {s=\frac{a+b+c}{2} }\\\\\\\sf {s=\frac{x+x+x}{2}=(x+12)\ cm}\\\\\\\\\\\sf {\Therefore Area\ of\ Triangle = \sqrt{s(s-a)(s-b)(s-c)} }\\\\\\\sf {60=\sqrt{(x+12)(x+12-x)(x+12-x)(x+12-24)} }\\\\\\\sf {60 = \sf {\sqrt[12]{\sf (x^{2}-144)}} }\\\\\\\sf {5=\sqrt{x^{2}-144} }\\\\\\\sf {x^{2}=144+25}\\\\\\\sf {x=\sqrt{169} }\\\\\\\sf {x=13}$

Semi-perimeter = (x+12) cm= (13+12) cm= 25 cm

Perimeter = 2 x 25 cm = 50 cm.