Question

the unequal side of isoscels triangle is 48cm and its perimeter is 108cm find the area of a triangle​

Answer 1

Answer:

108 - 48 = Sum of its other two same sides = 60 cm

So one side = 30 cm

By Pythagoras theorem the length of the median = $\sqrt{(30)^{2} - (24)^{2} }$

                                                                            = $\sqrt{900 - 576 }$

                                                                            = $\sqrt{324}$

                                                                            = 18 cm

Now the area of the triangle = 1/2 * Base * Height

                                            = 1/2 * 48 * 18

                                            = 432 $cm^{2}$

Hence the area of the Isosceles Triangle is 432 $cm^{2}$

Answer 2

A≈285.74cm²

a Side

48

cm

P Perimeter

108

cm