Question

the unequal sides of an isosceles triangle is 3cm more than one of its equal side. if the perimeter of the triangle is 84 cm find the length of the three side​

Answer 1

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$\sf \: = > \: let \: the \: equal \: side \: be \:( x)$

$= > \sf \: the \: unequal \: side \: will \: be \: \: x + 3$

$\sf \: now$

$\sf \: = > \: x + x + (x + 3) = 18$

$\sf \: = > \: 3x + 3 = 18$

$\sf \: = > \: 3x = 15$

$\sf \: = > \: x = 5$

$\sf \: we \: got \: that \: equal \: side \: is \:( 5 \: cm)$

$\sf \: so$

$\sf \: = > \: x + 3 \\ \sf \: = > \: 5 + 3$

$\sf \: = > \: 8$

Therefore:

Therefore:The sides of the triangle are 5 cm, 5 cm and 8 cm

hope it was helpful to you

Answer 2

$\: \: •\huge\bigstar{\underline{{\red{A}{\pink{n}{\color{blue}{s}{\color{gold}{w}{\color{aqua}{e}{\color{lime}{r}}}}}}}}}\huge\bigstar•$

therefore your answer is 8

hope it was helpful to you