Question

the unequal sides of an isosceles triangle measure 24 cm and its area is 60 square cm find perimeter​

Answer 1

Area of isosceles triangle= 1/2×24×height=60

So,12h= 60

Hence,h=60/12=5cm

Now height=5cm

base=24cm

So,hypotenuse=?

We know by Pythagoras theorem that (AB)²+(BC)²= (AC)²

Here

a=24/2=12cm (As base is divided into two parts by the altitude)

b=5cm

So,

(hypotenuse)²= (12)²+(5)²=169cm

So,side=hypotenuse=√169=13cm

So,

Perimeter=24cm+13cm+13cm=50cm

Answer 2

Answer:

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answer is 50 cm