Question

The unequal sides of an isosceles triangle measure 24cm and its area is 60cm square . find the perimeter of the given isosceles triangle.​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

Let the the triangle be ABC in which D is mid-point of AC

AC=24 , therefore AD=12cm

Area =60cm

2

and we know that area of triangle =

2

1

×AC×BD

then, 60=

2

1

×24×BD

BD=5cm

Now, by Pythagoras theorem

AB

2

=AD

2

+BD

2

AB=13

Now perimeter of ΔABC=AB+BC+AC=2AB+AC (two sides of isosceles triangle are equal)

Perimeter =26+24=50cm