Question

The uniform force of (2i+j)N acts
on a particle of mass 1kg.The
particle displaces from
position (3j+k)m to (5i+3j)
The work done by the force.
on the particle is a​

Answer 1

Answer:

F

=3

i

^

+

j

^

S

=

r

2

− r1

=2

i

^

+3

j

^

−2

k

^

W= F

.

S

=6+3+0=9J

Answer 2

Answer:

The work done by the force is - 1 J.

Explanation:

Given: Force, F = (2i + j) N

        Mass, M = 1 kg

   Initial position = (3j + k)

   Final position = (5i + 3j)

To find: The work done by the force on the particle.

Solution: For displacement, we have:

               s = (3i + k) - (5i + 3j)

               s = (- 2i + 3j + k) m

For work done, we have:

              W = F.s

              W = (2i + j). (- 2i + 3j + k)

              W = -4 + 3

              W = - 1 J

Hence, work done is - 1 J.