The uniform force of (2i+j)N acts
on a particle of mass 1kg.The
particle displaces from
position (3j+k)m to (5i+3j)
The work done by the force.
on the particle is a
Answers
Answered by
0
Answer:
F
=3
i
^
+
j
^
S
=
r
2
− r1
=2
i
^
+3
j
^
−2
k
^
W= F
.
S
=6+3+0=9J
Answered by
0
Answer:
The work done by the force is - 1 J.
Explanation:
Given: Force, F = (2i + j) N
Mass, M = 1 kg
Initial position = (3j + k)
Final position = (5i + 3j)
To find: The work done by the force on the particle.
Solution: For displacement, we have:
s = (3i + k) - (5i + 3j)
s = (- 2i + 3j + k) m
For work done, we have:
W = F.s
W = (2i + j). (- 2i + 3j + k)
W = -4 + 3
W = - 1 J
Hence, work done is - 1 J.
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