Chemistry, asked by mohammedbasim9793, 8 months ago

The unit cell of a metallic element is face centred cubic and the side of the cube is 540.2 pm. Calculate the density of a metal in gcm-3 is if its relative atomic mass is 202.4.

Answers

Answered by Jasleen0599
29

Given:

Edge of cube, a = 540.2 pm = 540.2 × 10⁻¹⁰ cm

Atomic mass, M = 202.4 gm

The unit cell is FCC.

To Find:

The density of the metal.

Calculation:

- For FCC, z = 4

- We know the formula:

V × NA × d = z × M

⇒ a³ × NA × d = z × M

⇒ d = (z × M)/(a³ × NA)

⇒ d = (4 × 202.4)/{(540.2 × 10⁻¹⁰)³ × 6.022 × 10²³)

⇒ d = 809.6/(157.64 × 10⁻²⁴ × 6.022 × 10²³)

⇒ d = 809.6/94.93

d = 8.528 gm/cm³

- So, the density of the given metallic element is 8.528 gm/cm³.

Answered by pritishah75
3

We know that,

Density-

d=

a

3

×NA

Z×M

Given :

Molar Mass(M)=108g/mol

Density (d)=10.5g/cm

3

Edge Length(a)=409pm

Z=

M

d×a

3

×N

A

Value of N

A

is N

A

=6.023×10

23

Z=

108

10.5×(409×10

−10

cm

3

)

3

×6.023×10

23

=4

Number of atoms =4

Hence the element is packed in FCC structure.

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