Question

The unit cell of an element of atomic mass 108 u and density 10.5 g cm-3 is a cube with edge
length, 409 pm. Find the type of unit cell of the crystal.
[Given : Avogadro's constant = 6.023 x 1023 mol |​

Answer 1

Answer:

Correct option is A)

We know that,

Density-

d=

a

3

×NA

Z×M

Given :

Molar Mass(M)=108g/mol

Density (d)=10.5g/cm

3

Edge Length(a)=409pm

Z=

M

d×a

3

×N

A

Value of N

A

is N

A

=6.023×10

23

Z=

108

10.5×(409×10

−10

cm

3

)

3

×6.023×10

23

=4

Number of atoms =4

Hence the element is packed in FCC structure.

Explanation:

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