Question

The unit cell of metalic silver is FCC . If radius of Ag atom is 144.4 pm calculate volume of Ag atom

Answer 1

Answer:

simple solution

Explanation:

we know the formula

density = mass* coordination number/avagadro_num* volume

so volume = mass* coordination number/avagadro_num* density

please check whether density of silver is given in your question

according to my idea density of silver is 10.490 g/cm^3

mass of silver = 107.8 g/mol

given radius= 144.4pm = 144.4 * 10^-10 cm

coordinatio number = z = 4

putting all values

density = 107.8* 4 / 6.022*10^23 * 10.490

solve this to get the density

alright i solved and answer is  6.82* 10^-23

i hope it is correct and hope it helps you