The unit cell of metallic
silver is fcc. If radius of Ag atom is 144.4 pm then calculate edge length of unit cell
Answers
Answered by
12
Answer:
a=408.4 pm
Explanation:
for fcc edge length a = 2√2r
= 2×√2 ×144.4 pm
= 408.4 pm
hope it will help you
Answered by
1
a=408.4 pm
Explanation:
for fcc edge length a = 2√2r
= 2×√2 ×144.4 pm
= 408.4 pm
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