The unit cell of metallic silver is fcc. If radius of Ag atom is 144.4 pm,
calculate (a) edge length of unit cell (b) volume of Ag atom
Answers
Answered by
1
a=408.4 pm
Explanation:
for fcc edge length a = 2√2r
= 2×√2 ×144.4 pm
= 408.4 pm
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Answered by
1
Answer:
a=408.4 pm
1
5.0
Explanation:
for fcc edge length a = 2√2r
= 2×√2 ×144.4 pm
= 408.4 pm
please mark me brain mark list
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