Chemistry, asked by dipikashelar47, 6 months ago

the unit cell of metallic silver is focused if radius of Ag atoms is 144.4 pm calculate
A edge length of unit cell
B volume of atoms
C that percentage of the volume of a unit cell,that is occupied by Ag atoms

Answers

Answered by sc670087
2

Given,

Atomic mass of silver  

=

108u

Atomic cell length,

a=

4.077×

10 −8

Atomic radius in FCC,

r=

4

a

2

=

4

4.077×

10

−8

2

=

1.44×

10 −8

\

Each silver unit cell contains 4 atom.

 Density

=

N

A

×a

3

4×atomicmassofsilver

=

6.02×

10

23

×

(4.077×

10

−10

)

3

4×108

=

10589.25kgm

−3

Hence, atomic radius

1.44×

10 −8

and density is

10589.25kgm -3 please mark me brilliant

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