The unit digit of 1' +11"+11111+........1111111111111111 is
Answers
Answer:
Consider the following composite series,
1+11+111+1111+…+(1111…n 1's)
=1+(1+10)+(1+10+100)+(1+10+100+1000)+…+(1+10+100+1000+…+10n−1G.P with n number of terms)
Each term of above series is sum of a G.P. whose first term is 1 & common ratio is 10 hence nth term of above series is Tn=1⋅(10n−1)10−1=10n−19
Hence, the sum (Sn) of n terms of such series having nth term Tn=10n−19 is given as
Sn=∑n1Tn=∑n110n−19=19∑n1(10n−1)=19(∑n110n−∑n11)
=19(10(10n−1)10−1−n)=181(10(10n−1)−9n)
Hence, the generalized formula to get sum of n terms of this composite series
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hence substituting n=5 in the above generalized formula for given series 1+11+111+1111+11111 having five terms, the sum is given as
1+11+111+1111+11111=181(10(105−1)−9⋅5)=12345
Alternatively, one can fairly easily add all five terms of given series as follows
1+11+111+1111+11111––––––––=12345
Step-by-step explanation:
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