the unit digit of a 2 digit no. is 3 and 7 times the sum of the digits is the no. itself.Find the number.
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let u=units digit=3
let t=tens digit
10t+u=number
..
7(u+t)=10t+u
7u+7t=10t+u
21+7t=10t+3
3t=18
t=6
10t+u=60+3=63
number=63
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