the unit digit of a two digit no is 3 and seven times the sum of the digits is the number itself. find the number
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Unit place is=3
Let digit at tens place be x
So 2 digit number= 10×x+3
=10x+3
Acc to question
10x+3= 7(x+3)
10x+3=7x+21
10x-7x=21-3
3x=18
X=6
Number= 10×6+3
=63 ans
Let digit at tens place be x
So 2 digit number= 10×x+3
=10x+3
Acc to question
10x+3= 7(x+3)
10x+3=7x+21
10x-7x=21-3
3x=18
X=6
Number= 10×6+3
=63 ans
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