Question

the unit digit of a two-digit number is 3 and seven times the sum of the digits is the number itself . find the number.

Answer 1

let the another digit =y
so the no is 10y+3
and by question the no is 7 (3+y)=10y+3
or,21+7y=10y+3
3y =18
y= 6
the no is 10*6+3=63

Answer 2

Step-by-step explanation:

• Unit of two digit number is 3

• Let the tens digit number be x

• The Number will be 10x + 3

1. Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.