The unit digit of a two-digit number is 3 and seven times the sum of the digit is the number itself •Find the number
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The number is 33
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Given; The unit digit of a two-digit number is 3 and seven times the sum of the digit is the number itself
To Find; the number
Solution It is given that The unit digit of a two-digit number is 3 and seven times the sum of the digit is the number itself
Let the unit digit be x and one digit be y then the number will 10y+x
According to question
x=3
7(x+y)=10y+x
7x+7y=10y+x
6x=3y
y=2x
y=6
So the number will be 60+3 that is 63
Hence the number is 63
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