Question

the unit digit of a two digit number is 3 and seven times the sum of the digitis the number itself.find the number

Answer 1

hi''let the number be xy

tens place = 10x

The unit digit of a two digit number is 3

so the number is 10x + 3

 seven times the sum of the digitis the number itself

lets form an euqation

7(x  + 3) = 10x  + 3

7x + 21 = 10x + 3

7x -10x = -21 +3

-3x = -18

x = 6

so the number is 63

hope it helps u

:)

Answer 2

Let the two digit number = 10x + y
Given that the unit digit is 3.
Therefore
y = 3

Given that seven times, the sum of the digits is the number itself
Therfore7 (x + y) = 10x + y
7 (x + 3) = 10x + 3
7x + 21 = 10x + 3
18 = 3x
x = 6

The number is 10x + y = 63.

Hope this helps you.