Math, asked by sahil8133, 1 year ago

The unit digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number

Answers

Answered by DiyaKhurana
19
tens digit = x
unit digit = 3
number = 10x +3      [as tens digit is multiplied by 10 to get on the tens place]        7( x + 3 ) = 10x + 3
7x + 21 = 10x +3
21 - 3 = 10x - 7x
18 = 3x
18÷3 = x 
 x = 6
∴ the number is 63

I hope its correct and it helps you! :-)

Answered by Anonymous
1

Answer:

  • Unit of two digit number is 3

  • Let the tens digit number be x

  • The Number will be 10x + 3

  • Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.

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