The unit digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number
Answers
Answered by
19
tens digit = x
unit digit = 3
number = 10x +3 [as tens digit is multiplied by 10 to get on the tens place] 7( x + 3 ) = 10x + 3
7x + 21 = 10x +3
21 - 3 = 10x - 7x
18 = 3x
18÷3 = x
x = 6
∴ the number is 63
I hope its correct and it helps you! :-)
unit digit = 3
number = 10x +3 [as tens digit is multiplied by 10 to get on the tens place] 7( x + 3 ) = 10x + 3
7x + 21 = 10x +3
21 - 3 = 10x - 7x
18 = 3x
18÷3 = x
x = 6
∴ the number is 63
I hope its correct and it helps you! :-)
Answered by
1
Answer:
- Unit of two digit number is 3
- Let the tens digit number be x
- The Number will be 10x + 3
- Sum of two digit number = x + 3
According to the question now :
➳ 7(x + 3) = 10x + 3
➳ 7x + 21 = 10x + 3
➳ 21 - 3 = 10x - 7x
➳ 18 = 3x
➳ x = 18/3
➳ x = 6
Therefore, the tens digit number is 6.
Hence,
The required number = 10x + 3 = 10(6) + 3 = 63.
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