Question

the unit digit of a two digit number is 3 and seven times the sum of the digits is the number itself . find the number

Answer 1

let the number =10×y+3

GIVEN

7(y+3)= 10×y+3

then

7y+21=10y+3

3y=18

y=6

and the number is 10×6+3

=63


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Answer 2

Answer:

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.