Question

the unit digit of a two digit number is 3 and seven times the sum of the digit is the number itself. find the number
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Answer 1

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Sol: Units digit of a two digit number = 3 Let the tens digit of the number be x. Number = 10x + 3 Sum of the digits = (x + 3) Given that 7 times the sum of the digits is the number itself. ⇒ 7(x + 3) = (10x + 3) ⇒ 7x + 21 = 10x + 3 ⇒ 10x - 7x = 21 - 3 ⇒ 3x = 18 ⇒ x = 6. Therefore, the digits in the tens place is 6 and the number is 63.

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Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

7(x + 3) = 10x + 3

7x + 21 = 10x + 3

21 - 3 = 10x - 7x

18 = 3x

x = 18/3

x = 6

x = 6Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.