The unit digit of a two digit number is 3 and the 7 times then the sum of the digit is the number itself find the number
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Units digit of a two digit number = 3
Let the tens digit of the number be x.
Number = 10x + 3
Sum of the digits = (x + 3)
according to the question
7(x + 3) = (10x + 3)
7x + 21 = 10x + 3
10x - 7x = 21 - 3
3x = 18
x = 6.
the number is 63
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