Question

the unit digit of a two digit number is 3 times of tens digit if digits are interchanged the new no so obtained is 36 more than the original no. find the original no. ?

Answer 1

Let the tens place digit be a

Unit place digit = 3a

According to question,

10(a) + 3a + 36 = 10(3a) + a

=> 13a + 36 = 31a

=> 18a = 36

=> a = 2

Required number = 10(2) + 3(2)

= 20 + 6

= 26