The unit digit of a two digit number is3 and seven times the sum of medigiys is the number itself .find the number
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Let the tens place digit be a
Unit place digit = 3
According to question,
7 ( Sum of digits) = Original number
=> 7 ( a + 3) = 10a + 3
=> 7a + 21 = 10a + 3
=> 21 - 3 = 10a - 7a
=> 3a = 18
=> a = 6
Required number = 10 × 6 + 3
= 63
Unit place digit = 3
According to question,
7 ( Sum of digits) = Original number
=> 7 ( a + 3) = 10a + 3
=> 7a + 21 = 10a + 3
=> 21 - 3 = 10a - 7a
=> 3a = 18
=> a = 6
Required number = 10 × 6 + 3
= 63
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