the unit digit of two digit number is 3 and 7 times of sum many digits is the number itself find the number
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hy
here is your answer
=================
➡let u=units digit=3
➡let t=tens digit
➡10t+u=number
➡7(u+t)=10t+u
➡7u+7t=10t+u
➡21+7t=10t+3
➡3t=18
➡t=6
➡10t+u=60+3=63
➡number=63
here is your answer
=================
➡let u=units digit=3
➡let t=tens digit
➡10t+u=number
➡7(u+t)=10t+u
➡7u+7t=10t+u
➡21+7t=10t+3
➡3t=18
➡t=6
➡10t+u=60+3=63
➡number=63
sapareleelavathi:
hay
tq
My pleasure :-)
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