Question

THE UNIT DIGIT OF TWO NUMBER IS 3 AND SEVEN TIMES THE SUM OF DIGIT IS THE NUMBER ITSELF FIND THE NUMBER

Answer 1

Answer:

let the digit at tens place be x

7(x+3) = 10x+3

7x+21=10x+3

3x=18

x=6

no. is 63

Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.