The unit digits of a two digit number is 3 and seven times the sum of digits ia the number itself. Find the number
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Answered by
1
Step-by-step explanation:
Unit of two digit number is 3
Let the tens digit number be x
The Number will be 10x + 3
Sum of two digit number = x + 3
According to the question now :
➳ 7(x + 3) = 10x + 3
➳ 7x + 21 = 10x + 3
➳ 21 - 3 = 10x - 7x
➳ 18 = 3x
➳ x = 18/3
➳ x = 6
Therefore, the tens digit number is 6.
Hence,
The required number = 10x + 3 = 10(6) + 3 = 63.
Answered by
0
Answer:
Let tens digit = x
Units digit = 3
∴Number = 3 + 10x
According to the condition,
7 (x + 3) = 3 + 10x
7x + 21 = 3 + 10x
21 – 3 = 10x – 7x
=> 3x = 18
x = 183
∴Number = 3 + 10x
= 3 + 10 x 6 = 3 + 60 = 63
Step-by-step explanation:
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