Question

The unit digits of a two digit number is 3 and seven times the sum of digits ia the number itself. Find the number

Answer 1

Step-by-step explanation:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.

Answer 2

Answer:

Let tens digit = x

Units digit = 3

∴Number = 3 + 10x

According to the condition,

7 (x + 3) = 3 + 10x

7x + 21 = 3 + 10x

21 – 3 = 10x – 7x

=> 3x = 18

x = 183

∴Number = 3 + 10x

= 3 + 10 x 6 = 3 + 60 = 63

Step-by-step explanation: