The unit of a two digit number is 3 and 7 times the sum of the digit is the number itself find the number
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Units digit of a number = 3
Let the tens digit of the number be x.
Number = 10x + 3
Sum of the digits = x + 3
According to the question,
7(x + 3) = 10x + 3
7x + 21 = 10x + 3
10x - 7x = 21- 3
3x = 18
x = 6
Therefore the digits in the tens place is 6 and the number is 63 .
Hope it helps you.....
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