the unit of digit of two digit number is 3 and 7 times the sum of the digits is the number itself. find the number.
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so,the number is 63
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The digit of the units place a two-digit number is 3
u=3
and seven times the sum of the digits is the number itself.
7(t+u) = 10t+u
Substituting u=3:
7(t+3) = 10t+3
7t+21 = 10t+3
-3t = -18
t= -18/-3
t = 6
Therefore, The digit on the tens place is 6
and the digit on the units place is 3,
So, the number is 63.
I hope this might help you:)
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