The unit of length convenient on the atomic scale is known as an Armstrong and is denoted by ; = 10⁻¹⁰ m. The size of a hydrogen atom is about . What is the total atomic volume in m³ of a mole of hydrogen atoms?
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Answered by
8
Hii friend,
# Answer- V = 3.144×10^-8 m^3
# Given-
Radius of hydrogen atom
r = 0.5 Å = 0.5×10^-10 m
# Formula-
Volume of hydrogen atom is calculated by formula,
V = 4/3 πr^3
V = 1.33×3.14×(0.5×10^-10)^3
V = 5.22×10^-31 m^3
One mole contains 6.023×10^22 atoms.
Hence total volume
= 5.22×10^-31 × 6.023×10^22
= 3.144×10^-8 m^3
Hence, volume of a mole of hydrogen atom is 3.144×10^-8 m^3
Hope that helped you...
# Answer- V = 3.144×10^-8 m^3
# Given-
Radius of hydrogen atom
r = 0.5 Å = 0.5×10^-10 m
# Formula-
Volume of hydrogen atom is calculated by formula,
V = 4/3 πr^3
V = 1.33×3.14×(0.5×10^-10)^3
V = 5.22×10^-31 m^3
One mole contains 6.023×10^22 atoms.
Hence total volume
= 5.22×10^-31 × 6.023×10^22
= 3.144×10^-8 m^3
Hence, volume of a mole of hydrogen atom is 3.144×10^-8 m^3
Hope that helped you...
Answered by
5
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Radius of hydrogen atom, r = 0.5 Angstrom= 0.5 × 10^–10 m
Volume of hydrogen atom
=4/3 πr^3
=(4/3)(22/7)(0.5×10^-10)^3
= 0.524×10^-30 m^3
1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.
Volume of 1 mole of hydrogen atoms = 6.023 × 1023 × 0.524 × 10–30 = 3.16 × 10–7 m3
I hope, this will help you
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