Question

The unit of length convenient on the atomic scale is known as an Armstrong and is denoted by $\AA$; $1 \AA$ = 10⁻¹⁰ m. The size of a hydrogen atom is about $0.5 \AA$. What is the total atomic volume in m³ of a mole of hydrogen atoms?

Answer 1

Hii friend,

# Answer- V = 3.144×10^-8 m^3

# Given-
Radius of hydrogen atom
r = 0.5 Å = 0.5×10^-10 m

# Formula-
Volume of hydrogen atom is calculated by formula,
V = 4/3 πr^3
V = 1.33×3.14×(0.5×10^-10)^3
V = 5.22×10^-31 m^3

One mole contains 6.023×10^22 atoms.
Hence total volume
= 5.22×10^-31 × 6.023×10^22
= 3.144×10^-8 m^3


Hence, volume of a mole of hydrogen atom is 3.144×10^-8 m^3

Hope that helped you...

Answer 2

==============ⓢⓦⓘⓖⓨ

$\huge\mathfrak\red{hello...frd\:swigy\:here}$

==============ⓢⓦⓘⓖⓨ

Radius of hydrogen atom, r = 0.5 Angstrom= 0.5 × 10^–10 m

Volume of hydrogen atom

=4/3 πr^3

=(4/3)(22/7)(0.5×10^-10)^3

= 0.524×10^-30 m^3

1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.

Volume of 1 mole of hydrogen atoms = 6.023 × 1023 × 0.524 × 10–30 = 3.16 × 10–7 m3

I hope, this will help you

=======================

$<marquee behaviour-move bigcolour-pink><h1>☺ThankYou✌</h1></marquee>$

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________