Physics, asked by sonkrvreou, 2 months ago

The unit of permittivity of free space, &,
is
(A) coulomb/newton-metre
[20
(B) newton-metre/coulomb
(C) coulomb/newton-metre?
(D) coulomb>/(newton-metre)2

Answers

Answered by ajr111

0

Answer:

Coulomb² / newton . metre² is the answer

also called Farad/meter

Explanation:

Hope it helps

Please mark as brainliest

Answered by yashsonkar658

1

Answer:

coulomb/newton-metre?

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