Question

The unit place digit of hcf of 2^2*3^2*5^3*7, 2^3*3^3*5^2*7^2 and 3*5*7*11 is

Answer 1

Step-by-step explanation:

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Answer 2

Given data: $2^2 X 3^2X5^3X7,2^3X3^3X5^2X7^2$ and $3X5X7X11$

To find: The unit place digit of HCF.

Solution:

HCF is the highest common factor, In which we need to consider the common among the given 3 factors.

$2^2 X 3^2X5^3X7$

$2^3X3^3X5^2X7^2$

$3X5X7X11$

The HCF of given 3 factors are 3 × 5 × 7 = 105.

Hence the unit place digit of HCF is 5.