The unit's digit of a two digit number is 3 and seven time the sum of the digits is the number itself. The number is?
Answers
Answered by
4
the number is 63
(6+3)×7 = 63
Answered by
19
Let the tens digit of that number be y
The number will be = 10y + 3
According to the Question,
7 ( y + 3) = 10y + 3
Now, we shall solve this linear equation in one variable.
7 ( y + 3) = 10y + 3
=> 7y + 21 = 10y + 3
=> 3y = 18
=> y = 6
If y = 6 the number will be 63. [Ans]
VERIFICATION :-
LHS = 7 (6 + 3)
= 7 × 9
= 63
= RHS
Hence, our answer is correct !
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