Question

the unit vector along i^ j^ is​

Answer 1

Answer:

Unit vector along(i+j)is

∣i+j∣

(i+j)

∣i+j∣ is magnitude of(i+j)

we know,

i and j are perpendicular to each other

So, ∣i+j∣=

i

2

+j

2

+2ijcos90

o

1+1

=

2

hence, unit vector along (i+j)is

√2

(i+j)....