Physics, asked by nemmojuvishnu, 1 month ago

The unit vector along i^+j^ is​

Answers

Answered by varshapallam17
1

Answer:

unit vector of i^+j^ = \frac{i+j}{| i+j | }

                       |i +j| = \sqrt{i^2+j^2+2ijcos90}

                               =   \sqrt{1+1\\}

                               =  \sqrt{2\\}  

    so unit vector along i^+j^ is \frac{i+j}{\sqrt{2} }

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